Binary Number with Alternating Bits

LeetCode題目: 693. Binary Number with Alternating Bits

My solution:

/**
 * @param {number} n
 * @return {boolean}
 */
let hasAlternatingBits = n => {
    let binary = n.toString(2);
    for(let i=0; i<binary.length; i++) {
        if(binary[i] === binary[i+1]) return false;
    }
    return true;
};